In the figure, RST is parallel to WXY and the line WT cuts ∠SWY into half. Given that TW and SX are straight lines, ∠RSW = 48°, ∠WXV = 32° and ∠SVT = 114°, find
- ∠c
- ∠e
- ∠d
(a)
∠WVX = ∠SVT = 114° (Vertically opposite angles)
∠c
= 180° - 114° - 32°
= 34° (Angles sum of triangle)
(b)
∠e
= 180° - 34°
= 146° (Interior angles)
(c)
∠d
= 180° - 34° - 34° - 32°
= 100° (Angles sum of triangle)
Answer(s): (a) 34°; (b) 146°; (c) 100°