In the figure, KLM is parallel to QRS and the line QM cuts ∠LQS into half. Given that MQ and LR are straight lines, ∠KLQ = 47°, ∠QRP = 37° and ∠LPM = 115°, find
- ∠d
- ∠f
- ∠e
(a)
∠QPR = ∠LPM = 115° (Vertically opposite angles)
∠d
= 180° - 115° - 37°
= 28° (Angles sum of triangle)
(b)
∠f
= 180° - 28°
= 152° (Interior angles)
(c)
∠e
= 180° - 28° - 28° - 37°
= 96° (Angles sum of triangle)
Answer(s): (a) 28°; (b) 152°; (c) 96°