In the figure, EFG is parallel to KLM and the line KG cuts ∠FKM into half. Given that GK and FL are straight lines, ∠EFK = 43°, ∠KLJ = 38° and ∠FJG = 116°, find
- ∠n
- ∠q
- ∠p
(a)
∠KJL = ∠FJG = 116° (Vertically opposite angles)
∠n
= 180° - 116° - 38°
= 26° (Angles sum of triangle)
(b)
∠q
= 180° - 26°
= 154° (Interior angles)
(c)
∠p
= 180° - 26° - 26° - 38°
= 99° (Angles sum of triangle)
Answer(s): (a) 26°; (b) 154°; (c) 99°