In the figure, PQR is parallel to UVW and the line UR cuts ∠QUW into half. Given that RU and QV are straight lines, ∠PQU = 49°, ∠UVT = 37° and ∠QTR = 119°, find
- ∠n
- ∠q
- ∠p
(a)
∠UTV = ∠QTR = 119° (Vertically opposite angles)
∠n
= 180° - 119° - 37°
= 24° (Angles sum of triangle)
(b)
∠q
= 180° - 24°
= 156° (Interior angles)
(c)
∠p
= 180° - 24° - 24° - 37°
= 94° (Angles sum of triangle)
Answer(s): (a) 24°; (b) 156°; (c) 94°