In the figure, PQR is parallel to UVW and the line UR cuts ∠QUW into half. Given that RU and QV are straight lines, ∠PQU = 44°, ∠UVT = 36° and ∠QTR = 120°, find
- ∠k
- ∠n
- ∠m
(a)
∠UTV = ∠QTR = 120° (Vertically opposite angles)
∠k
= 180° - 120° - 36°
= 24° (Angles sum of triangle)
(b)
∠n
= 180° - 24°
= 156° (Interior angles)
(c)
∠m
= 180° - 24° - 24° - 36°
= 100° (Angles sum of triangle)
Answer(s): (a) 24°; (b) 156°; (c) 100°