In the figure, MNP is parallel to STU and the line SP cuts ∠NSU into half. Given that PS and NT are straight lines, ∠MNS = 42°, ∠STR = 32° and ∠NRP = 110°, find
- ∠q
- ∠s
- ∠r
(a)
∠SRT = ∠NRP = 110° (Vertically opposite angles)
∠q
= 180° - 110° - 32°
= 38° (Angles sum of triangle)
(b)
∠s
= 180° - 38°
= 142° (Interior angles)
(c)
∠r
= 180° - 38° - 38° - 32°
= 106° (Angles sum of triangle)
Answer(s): (a) 38°; (b) 142°; (c) 106°