In the figure, PQR is parallel to UVW and the line UR cuts ∠QUW into half. Given that RU and QV are straight lines, ∠PQU = 48°, ∠UVT = 32° and ∠QTR = 115°, find
- ∠b
- ∠d
- ∠c
(a)
∠UTV = ∠QTR = 115° (Vertically opposite angles)
∠b
= 180° - 115° - 32°
= 33° (Angles sum of triangle)
(b)
∠d
= 180° - 33°
= 147° (Interior angles)
(c)
∠c
= 180° - 33° - 33° - 32°
= 100° (Angles sum of triangle)
Answer(s): (a) 33°; (b) 147°; (c) 100°