In the figure, RST is parallel to WXY and the line WT cuts ∠SWY into half. Given that TW and SX are straight lines, ∠RSW = 46°, ∠WXV = 33° and ∠SVT = 111°, find
- ∠g
- ∠i
- ∠h
(a)
∠WVX = ∠SVT = 111° (Vertically opposite angles)
∠g
= 180° - 111° - 33°
= 36° (Angles sum of triangle)
(b)
∠i
= 180° - 36°
= 144° (Interior angles)
(c)
∠h
= 180° - 36° - 36° - 33°
= 101° (Angles sum of triangle)
Answer(s): (a) 36°; (b) 144°; (c) 101°