In the figure, JKL is parallel to PQR and the line PL cuts ∠KPR into half. Given that LP and KQ are straight lines, ∠JKP = 44°, ∠PQN = 35° and ∠KNL = 117°, find
- ∠w
- ∠y
- ∠x
(a)
∠PNQ = ∠KNL = 117° (Vertically opposite angles)
∠w
= 180° - 117° - 35°
= 28° (Angles sum of triangle)
(b)
∠y
= 180° - 28°
= 152° (Interior angles)
(c)
∠x
= 180° - 28° - 28° - 35°
= 101° (Angles sum of triangle)
Answer(s): (a) 28°; (b) 152°; (c) 101°