In the figure, EFG is parallel to KLM and the line KG cuts ∠FKM into half. Given that GK and FL are straight lines, ∠EFK = 48°, ∠KLJ = 38° and ∠FJG = 120°, find
- ∠r
- ∠t
- ∠s
(a)
∠KJL = ∠FJG = 120° (Vertically opposite angles)
∠r
= 180° - 120° - 38°
= 22° (Angles sum of triangle)
(b)
∠t
= 180° - 22°
= 158° (Interior angles)
(c)
∠s
= 180° - 22° - 22° - 38°
= 94° (Angles sum of triangle)
Answer(s): (a) 22°; (b) 158°; (c) 94°