In the figure, MNP is parallel to STU and the line SP cuts ∠NSU into half. Given that PS and NT are straight lines, ∠MNS = 42°, ∠STR = 39° and ∠NRP = 119°, find
- ∠f
- ∠h
- ∠g
(a)
∠SRT = ∠NRP = 119° (Vertically opposite angles)
∠f
= 180° - 119° - 39°
= 22° (Angles sum of triangle)
(b)
∠h
= 180° - 22°
= 158° (Interior angles)
(c)
∠g
= 180° - 22° - 22° - 39°
= 99° (Angles sum of triangle)
Answer(s): (a) 22°; (b) 158°; (c) 99°