In the figure, DEF is parallel to JKL and the line JF cuts ∠EJL into half. Given that FJ and EK are straight lines, ∠DEJ = 46°, ∠JKH = 42° and ∠EHF = 114°, find
- ∠t
- ∠w
- ∠v
(a)
∠JHK = ∠EHF = 114° (Vertically opposite angles)
∠t
= 180° - 114° - 42°
= 24° (Angles sum of triangle)
(b)
∠w
= 180° - 24°
= 156° (Interior angles)
(c)
∠v
= 180° - 24° - 24° - 42°
= 92° (Angles sum of triangle)
Answer(s): (a) 24°; (b) 156°; (c) 92°