In the figure, JKL is parallel to PQR and the line PL cuts ∠KPR into half. Given that LP and KQ are straight lines, ∠JKP = 45°, ∠PQN = 38° and ∠KNL = 115°, find
- ∠j
- ∠m
- ∠k
(a)
∠PNQ = ∠KNL = 115° (Vertically opposite angles)
∠j
= 180° - 115° - 38°
= 27° (Angles sum of triangle)
(b)
∠m
= 180° - 27°
= 153° (Interior angles)
(c)
∠k
= 180° - 27° - 27° - 38°
= 97° (Angles sum of triangle)
Answer(s): (a) 27°; (b) 153°; (c) 97°