In the figure, EFG is parallel to KLM and the line KG cuts ∠FKM into half. Given that GK and FL are straight lines, ∠EFK = 50°, ∠KLJ = 41° and ∠FJG = 119°, find
- ∠f
- ∠h
- ∠g
(a)
∠KJL = ∠FJG = 119° (Vertically opposite angles)
∠f
= 180° - 119° - 41°
= 20° (Angles sum of triangle)
(b)
∠h
= 180° - 20°
= 160° (Interior angles)
(c)
∠g
= 180° - 20° - 20° - 41°
= 89° (Angles sum of triangle)
Answer(s): (a) 20°; (b) 160°; (c) 89°