In the figure, QRS is parallel to VWX and the line VS cuts ∠RVX into half. Given that SV and RW are straight lines, ∠QRV = 50°, ∠VWU = 36° and ∠RUS = 116°, find
- ∠b
- ∠d
- ∠c
(a)
∠VUW = ∠RUS = 116° (Vertically opposite angles)
∠b
= 180° - 116° - 36°
= 28° (Angles sum of triangle)
(b)
∠d
= 180° - 28°
= 152° (Interior angles)
(c)
∠c
= 180° - 28° - 28° - 36°
= 94° (Angles sum of triangle)
Answer(s): (a) 28°; (b) 152°; (c) 94°