In the figure, HJK is parallel to NPQ and the line NK cuts ∠JNQ into half. Given that KN and JP are straight lines, ∠HJN = 46°, ∠NPM = 33° and ∠JMK = 114°, find
- ∠g
- ∠i
- ∠h
(a)
∠NMP = ∠JMK = 114° (Vertically opposite angles)
∠g
= 180° - 114° - 33°
= 33° (Angles sum of triangle)
(b)
∠i
= 180° - 33°
= 147° (Interior angles)
(c)
∠h
= 180° - 33° - 33° - 33°
= 101° (Angles sum of triangle)
Answer(s): (a) 33°; (b) 147°; (c) 101°