In the figure, EFG is parallel to KLM and the line KG cuts ∠FKM into half. Given that GK and FL are straight lines, ∠EFK = 49°, ∠KLJ = 39° and ∠FJG = 111°, find
- ∠b
- ∠d
- ∠c
(a)
∠KJL = ∠FJG = 111° (Vertically opposite angles)
∠b
= 180° - 111° - 39°
= 30° (Angles sum of triangle)
(b)
∠d
= 180° - 30°
= 150° (Interior angles)
(c)
∠c
= 180° - 30° - 30° - 39°
= 92° (Angles sum of triangle)
Answer(s): (a) 30°; (b) 150°; (c) 92°