In the figure, DEF is parallel to JKL and the line JF cuts ∠EJL into half. Given that FJ and EK are straight lines, ∠DEJ = 44°, ∠JKH = 36° and ∠EHF = 115°, find
- ∠d
- ∠f
- ∠e
(a)
∠JHK = ∠EHF = 115° (Vertically opposite angles)
∠d
= 180° - 115° - 36°
= 29° (Angles sum of triangle)
(b)
∠f
= 180° - 29°
= 151° (Interior angles)
(c)
∠e
= 180° - 29° - 29° - 36°
= 100° (Angles sum of triangle)
Answer(s): (a) 29°; (b) 151°; (c) 100°