A list of 16 numbers has an average of 345. When two numbers are deleted from the list, the average of the remaining numbers is 303.
- What is the sum of 16 numbers?
- What is the bigger number between the two numbers that have been deleted given that the difference between the two numbers is 6?
(a)
Sum of the 16 numbers
= 16 x 345
= 5520
(b)
Remaining numbers
= 16 - 2
= 14
Sum of the remaining numbers
= 303 x 14
= 4242
Sum of the two numbers
= 5520 - 4242
= 1278
Smaller number = 1 u
Bigger number = 1 u + 6
Total = 1 u + 1 u + 6 = 2 u + 6
2 u + 6 = 1278
2 u = 1278 - 6
2 u = 1272
1 u = 1272 ÷ 2 = 636
Bigger number
= 1 u + 6
= 636 + 6
= 642
Answer(s): (a) 5520; (b) 642