A list of 14 numbers has an average of 339. When two numbers are deleted from the list, the average of the remaining numbers is 313.
- What is the sum of 14 numbers?
- What is the bigger number between the two numbers that have been deleted given that the difference between the two numbers is 6?
(a)
Sum of the 14 numbers
= 14 x 339
= 4746
(b)
Remaining numbers
= 14 - 2
= 12
Sum of the remaining numbers
= 313 x 12
= 3756
Sum of the two numbers
= 4746 - 3756
= 990
Smaller number = 1 u
Bigger number = 1 u + 6
Total = 1 u + 1 u + 6 = 2 u + 6
2 u + 6 = 990
2 u = 990 - 6
2 u = 984
1 u = 984 ÷ 2 = 492
Bigger number
= 1 u + 6
= 492 + 6
= 498
Answer(s): (a) 4746; (b) 498