A list of 16 numbers has an average of 333. When two numbers are deleted from the list, the average of the remaining numbers is 311.
- What is the sum of 16 numbers?
- What is the bigger number between the two numbers that have been deleted given that the difference between the two numbers is 4?
(a)
Sum of the 16 numbers
= 16 x 333
= 5328
(b)
Remaining numbers
= 16 - 2
= 14
Sum of the remaining numbers
= 311 x 14
= 4354
Sum of the two numbers
= 5328 - 4354
= 974
Smaller number = 1 u
Bigger number = 1 u + 4
Total = 1 u + 1 u + 4 = 2 u + 4
2 u + 4 = 974
2 u = 974 - 4
2 u = 970
1 u = 970 ÷ 2 = 485
Bigger number
= 1 u + 4
= 485 + 4
= 489
Answer(s): (a) 5328; (b) 489