A list of 16 numbers has an average of 348. When two numbers are deleted from the list, the average of the remaining numbers is 320.
- What is the sum of 16 numbers?
- What is the bigger number between the two numbers that have been deleted given that the difference between the two numbers is 2?
(a)
Sum of the 16 numbers
= 16 x 348
= 5568
(b)
Remaining numbers
= 16 - 2
= 14
Sum of the remaining numbers
= 320 x 14
= 4480
Sum of the two numbers
= 5568 - 4480
= 1088
Smaller number = 1 u
Bigger number = 1 u + 2
Total = 1 u + 1 u + 2 = 2 u + 2
2 u + 2 = 1088
2 u = 1088 - 2
2 u = 1086
1 u = 1086 ÷ 2 = 543
Bigger number
= 1 u + 2
= 543 + 2
= 545
Answer(s): (a) 5568; (b) 545