A list of 16 numbers has an average of 335. When two numbers are deleted from the list, the average of the remaining numbers is 314.
- What is the sum of 16 numbers?
- What is the bigger number between the two numbers that have been deleted given that the difference between the two numbers is 2?
(a)
Sum of the 16 numbers
= 16 x 335
= 5360
(b)
Remaining numbers
= 16 - 2
= 14
Sum of the remaining numbers
= 314 x 14
= 4396
Sum of the two numbers
= 5360 - 4396
= 964
Smaller number = 1 u
Bigger number = 1 u + 2
Total = 1 u + 1 u + 2 = 2 u + 2
2 u + 2 = 964
2 u = 964 - 2
2 u = 962
1 u = 962 ÷ 2 = 481
Bigger number
= 1 u + 2
= 481 + 2
= 483
Answer(s): (a) 5360; (b) 483