A list of 12 numbers has an average of 346. When two numbers are deleted from the list, the average of the remaining numbers is 313.
- What is the sum of 12 numbers?
- What is the bigger number between the two numbers that have been deleted given that the difference between the two numbers is 2?
(a)
Sum of the 12 numbers
= 12 x 346
= 4152
(b)
Remaining numbers
= 12 - 2
= 10
Sum of the remaining numbers
= 313 x 10
= 3130
Sum of the two numbers
= 4152 - 3130
= 1022
Smaller number = 1 u
Bigger number = 1 u + 2
Total = 1 u + 1 u + 2 = 2 u + 2
2 u + 2 = 1022
2 u = 1022 - 2
2 u = 1020
1 u = 1020 ÷ 2 = 510
Bigger number
= 1 u + 2
= 510 + 2
= 512
Answer(s): (a) 4152; (b) 512