A list of 13 numbers has an average of 333. When two numbers are deleted from the list, the average of the remaining numbers is 308.
- What is the sum of 13 numbers?
- What is the bigger number between the two numbers that have been deleted given that the difference between the two numbers is 5?
(a)
Sum of the 13 numbers
= 13 x 333
= 4329
(b)
Remaining numbers
= 13 - 2
= 11
Sum of the remaining numbers
= 308 x 11
= 3388
Sum of the two numbers
= 4329 - 3388
= 941
Smaller number = 1 u
Bigger number = 1 u + 5
Total = 1 u + 1 u + 5 = 2 u + 5
2 u + 5 = 941
2 u = 941 - 5
2 u = 936
1 u = 936 ÷ 2 = 468
Bigger number
= 1 u + 5
= 468 + 5
= 473
Answer(s): (a) 4329; (b) 473