A list of 12 numbers has an average of 344. When two numbers are deleted from the list, the average of the remaining numbers is 323.
- What is the sum of 12 numbers?
- What is the bigger number between the two numbers that have been deleted given that the difference between the two numbers is 6?
(a)
Sum of the 12 numbers
= 12 x 344
= 4128
(b)
Remaining numbers
= 12 - 2
= 10
Sum of the remaining numbers
= 323 x 10
= 3230
Sum of the two numbers
= 4128 - 3230
= 898
Smaller number = 1 u
Bigger number = 1 u + 6
Total = 1 u + 1 u + 6 = 2 u + 6
2 u + 6 = 898
2 u = 898 - 6
2 u = 892
1 u = 892 ÷ 2 = 446
Bigger number
= 1 u + 6
= 446 + 6
= 452
Answer(s): (a) 4128; (b) 452