A list of 13 numbers has an average of 347. When two numbers are deleted from the list, the average of the remaining numbers is 303.
- What is the sum of 13 numbers?
- What is the bigger number between the two numbers that have been deleted given that the difference between the two numbers is 6?
(a)
Sum of the 13 numbers
= 13 x 347
= 4511
(b)
Remaining numbers
= 13 - 2
= 11
Sum of the remaining numbers
= 303 x 11
= 3333
Sum of the two numbers
= 4511 - 3333
= 1178
Smaller number = 1 u
Bigger number = 1 u + 6
Total = 1 u + 1 u + 6 = 2 u + 6
2 u + 6 = 1178
2 u = 1178 - 6
2 u = 1172
1 u = 1172 ÷ 2 = 586
Bigger number
= 1 u + 6
= 586 + 6
= 592
Answer(s): (a) 4511; (b) 592