A list of 13 numbers has an average of 333. When two numbers are deleted from the list, the average of the remaining numbers is 306.
- What is the sum of 13 numbers?
- What is the bigger number between the two numbers that have been deleted given that the difference between the two numbers is 3?
(a)
Sum of the 13 numbers
= 13 x 333
= 4329
(b)
Remaining numbers
= 13 - 2
= 11
Sum of the remaining numbers
= 306 x 11
= 3366
Sum of the two numbers
= 4329 - 3366
= 963
Smaller number = 1 u
Bigger number = 1 u + 3
Total = 1 u + 1 u + 3 = 2 u + 3
2 u + 3 = 963
2 u = 963 - 3
2 u = 960
1 u = 960 ÷ 2 = 480
Bigger number
= 1 u + 3
= 480 + 3
= 483
Answer(s): (a) 4329; (b) 483