A list of 13 numbers has an average of 337. When two numbers are deleted from the list, the average of the remaining numbers is 318.
- What is the sum of 13 numbers?
- What is the bigger number between the two numbers that have been deleted given that the difference between the two numbers is 5?
(a)
Sum of the 13 numbers
= 13 x 337
= 4381
(b)
Remaining numbers
= 13 - 2
= 11
Sum of the remaining numbers
= 318 x 11
= 3498
Sum of the two numbers
= 4381 - 3498
= 883
Smaller number = 1 u
Bigger number = 1 u + 5
Total = 1 u + 1 u + 5 = 2 u + 5
2 u + 5 = 883
2 u = 883 - 5
2 u = 878
1 u = 878 ÷ 2 = 439
Bigger number
= 1 u + 5
= 439 + 5
= 444
Answer(s): (a) 4381; (b) 444