A list of 16 numbers has an average of 340. When two numbers are deleted from the list, the average of the remaining numbers is 316.
- What is the sum of 16 numbers?
- What is the bigger number between the two numbers that have been deleted given that the difference between the two numbers is 2?
(a)
Sum of the 16 numbers
= 16 x 340
= 5440
(b)
Remaining numbers
= 16 - 2
= 14
Sum of the remaining numbers
= 316 x 14
= 4424
Sum of the two numbers
= 5440 - 4424
= 1016
Smaller number = 1 u
Bigger number = 1 u + 2
Total = 1 u + 1 u + 2 = 2 u + 2
2 u + 2 = 1016
2 u = 1016 - 2
2 u = 1014
1 u = 1014 ÷ 2 = 507
Bigger number
= 1 u + 2
= 507 + 2
= 509
Answer(s): (a) 5440; (b) 509