A list of 13 numbers has an average of 332. When two numbers are deleted from the list, the average of the remaining numbers is 307.
- What is the sum of 13 numbers?
- What is the bigger number between the two numbers that have been deleted given that the difference between the two numbers is 1?
(a)
Sum of the 13 numbers
= 13 x 332
= 4316
(b)
Remaining numbers
= 13 - 2
= 11
Sum of the remaining numbers
= 307 x 11
= 3377
Sum of the two numbers
= 4316 - 3377
= 939
Smaller number = 1 u
Bigger number = 1 u + 1
Total = 1 u + 1 u + 1 = 2 u + 1
2 u + 1 = 939
2 u = 939 - 1
2 u = 938
1 u = 938 ÷ 2 = 469
Bigger number
= 1 u + 1
= 469 + 1
= 470
Answer(s): (a) 4316; (b) 470