A list of 16 numbers has an average of 344. When two numbers are deleted from the list, the average of the remaining numbers is 302.
- What is the sum of 16 numbers?
- What is the bigger number between the two numbers that have been deleted given that the difference between the two numbers is 6?
(a)
Sum of the 16 numbers
= 16 x 344
= 5504
(b)
Remaining numbers
= 16 - 2
= 14
Sum of the remaining numbers
= 302 x 14
= 4228
Sum of the two numbers
= 5504 - 4228
= 1276
Smaller number = 1 u
Bigger number = 1 u + 6
Total = 1 u + 1 u + 6 = 2 u + 6
2 u + 6 = 1276
2 u = 1276 - 6
2 u = 1270
1 u = 1270 ÷ 2 = 635
Bigger number
= 1 u + 6
= 635 + 6
= 641
Answer(s): (a) 5504; (b) 641