A list of 16 numbers has an average of 332. When two numbers are deleted from the list, the average of the remaining numbers is 325.
- What is the sum of 16 numbers?
- What is the bigger number between the two numbers that have been deleted given that the difference between the two numbers is 2?
(a)
Sum of the 16 numbers
= 16 x 332
= 5312
(b)
Remaining numbers
= 16 - 2
= 14
Sum of the remaining numbers
= 325 x 14
= 4550
Sum of the two numbers
= 5312 - 4550
= 762
Smaller number = 1 u
Bigger number = 1 u + 2
Total = 1 u + 1 u + 2 = 2 u + 2
2 u + 2 = 762
2 u = 762 - 2
2 u = 760
1 u = 760 ÷ 2 = 380
Bigger number
= 1 u + 2
= 380 + 2
= 382
Answer(s): (a) 5312; (b) 382