Nick was training for a swimming competition. On Day 1 of his training, he swam 200 m. On Day 2, he swam 0.1 km more than Day 1. For each subsequent training session, he swam a distance of 0.1 km more than the previous training session.
- On Day 5 of his training session, how far did he swim? Give your answer in km.
- On which day did he swim a distance of 3 km?
(a)
1000 m = 1 km
200 m = 0.2 km
Pattern for the distance swam
Day 1: ((1 - 1) x 0.1) + 0.2 = 0.2
Day 2: ((2 - 1) x 0.1) + 0.2 = 0.3
Day 3: ((3 - 1) x 0.1) + 0.2 = 0.4
Formula
Distance swam = ((Number of day - 1) x 0.1) + 0.2
Distance swam on Day 5
= [(5 - 1) x 0.1] + 0.2
= 4 x 0.1 + 0.2
= 0.4 + 0.2
= 0.6 km
(b)
Number of days he swam 3 km
= [(3 - 0.2) ÷ 0.1] + 1
= 2.8 ÷ 0.1 + 1
= 28 + 1
= 29
Answer(s): (a) 0.6 km; (b) 29