Emma, Hazel and Pamela were each given a piece of wire of equal length. Emma cut hers into equal lengths of 4 m, Hazel cut hers into equal lengths of 8 m, and Pamela cut hers into equal lengths of 10 m. If there were no remainder in each case, find the shortest length of wire given to each of them.
Multiples of 4: 4, 8, 12, 16, 20, 24, 28, 32, 36, 40
Multiples of 8: 8, 16, 24, 32, 40
Multiples of 10: 10, 20, 30, 40
Shortest length of wire given to each of them
= Lowest common multiple of 4 m, 8 m and 10 m
= 40 m
Answer(s): 40 m