Mrs. Ken has 15 candy canes, 18 sweets and 30 puffs to be placed into the goodie packets.
- What is the maximum number of goodie packets Mrs Ken needs to pack these items equally into without any left over?
- How many items will there be in each packet?
(a)
Maximum number of goodie packets
= Highest common factor of 15, 18 and 30
= 3
(b)
Number of candy canes in each packet
= 15 ÷ 3
= 5
Number of sweets in each packet
= 18 ÷ 3
= 6
Number of puffs in each packet
= 30 ÷ 3
= 10
Number of items in each packet
= 5 + 6 + 10
= 21
Answer(s):(a) 3; (b) 21