Mr. Chong has some markers. If he ties them in bundles of 7, he will have 4 extra markers. If he ties them in bundles of 8, he would be short of 3 markers. What is the smallest possible number of markers Mr. Chong has?
Multiples of 7: 7, 14, 21, 28, 35, 42, 49
Multiples of 7 (+4): 11, 18, 25, 32, 39, 46, 53
Multiples of 8: 8, 16, 24, 32, 40, 48, 56
Multiples of 8 (-3): 5, 13, 21, 29, 37, 45, 53
Smallest possible number of markers that Mr. Chong has = 53
Answer(s): 53
