Marion has 25 rings more than Jane. If Jane gives Marion 8 rings, how many less rings will Jane have than Marion?
| |
Jane |
Marion |
| Before |
1 u |
1 u + 25 |
| Change |
- 8 |
+ 8 |
| After |
1 u - 8 |
1 u + 33 |
Before
Number of rings that Jane has at first = 1 u
Number of rings that Marion has at first = 1 u + 25
After
Number of rings that Jane will have in the end = 1 u - 8
Number of rings that Marion will have in the end = 1 u + 25 + 8 = 1 u + 33
Number of rings that Jane will have less than Marion
= 33 + 8
= 41
Answer(s): 41
