Yen has 43 rings more than Abi. If Abi gives Yen 12 rings, how many less rings will Abi have than Yen?
| |
Abi |
Yen |
| Before |
1 u |
1 u + 43 |
| Change |
- 12 |
+ 12 |
| After |
1 u - 12 |
1 u + 55 |
Before
Number of rings that Abi has at first = 1 u
Number of rings that Yen has at first = 1 u + 43
After
Number of rings that Abi will have in the end = 1 u - 12
Number of rings that Yen will have in the end = 1 u + 43 + 12 = 1 u + 55
Number of rings that Abi will have less than Yen
= 55 + 12
= 67
Answer(s): 67
