Sam and Ahmad have a total of 72 coins. If Sam gives Ahmad 21 coins, Ahmad will have 5 times as many coins as him. Find
(a) Sam's coins
(b) Ahmad's coins
|
Sam |
Ahmad |
Total |
Before |
1 u + 21 |
5 u - 21 |
72 |
Change |
- 21 |
+ 21 |
|
After |
1 u |
5 u |
6 u |
(a)
Total number of coins
= 1 u + 5 u
= 6 u
6 u = 72
1 u = 72 ÷ 6 = 12
Number of coins that Sam has
= 1 u + 21
= 12 + 21
= 33
(b)
Number of coins that Ahmad has
= 72 - 33
= 39
Answer(s): (a) 33; (b) 39