Andy and Luis have a total of 52 beads. If Andy gives Luis 23 beads, Luis will have 3 times as many beads as him. Find
(a) Andy's beads
(b) Luis's beads
|
Andy |
Luis |
Total |
Before |
1 u + 23 |
3 u - 23 |
52 |
Change |
- 23 |
+ 23 |
|
After |
1 u |
3 u |
4 u |
(a)
Total number of beads
= 1 u + 3 u
= 4 u
4 u = 52
1 u = 52 ÷ 4 = 13
Number of beads that Andy has
= 1 u + 23
= 13 + 23
= 36
(b)
Number of beads that Luis has
= 52 - 36
= 16
Answer(s): (a) 36; (b) 16