Fred and Xavier have a total of 77 stamps. If Fred gives Xavier 40 stamps, Xavier will have 6 times as many stamps as him. Find
(a) Fred's stamps
(b) Xavier's stamps
|
Fred |
Xavier |
Total |
Before |
1 u + 40 |
6 u - 40 |
77 |
Change |
- 40 |
+ 40 |
|
After |
1 u |
6 u |
7 u |
(a)
Total number of stamps
= 1 u + 6 u
= 7 u
7 u = 77
1 u = 77 ÷ 7 = 11
Number of stamps that Fred has
= 1 u + 40
= 11 + 40
= 51
(b)
Number of stamps that Xavier has
= 77 - 51
= 26
Answer(s): (a) 51; (b) 26