Riordan and Dylan have a total of 70 coins. If Riordan gives Dylan 43 coins, Dylan will have 6 times as many coins as him. Find
(a) Riordan's coins
(b) Dylan's coins
|
Riordan |
Dylan |
Total |
Before |
1 u + 43 |
6 u - 43 |
70 |
Change |
- 43 |
+ 43 |
|
After |
1 u |
6 u |
7 u |
(a)
Total number of coins
= 1 u + 6 u
= 7 u
7 u = 70
1 u = 70 ÷ 7 = 10
Number of coins that Riordan has
= 1 u + 43
= 10 + 43
= 53
(b)
Number of coins that Dylan has
= 70 - 53
= 17
Answer(s): (a) 53; (b) 17