Cody and Xavier have a total of 68 stickers. If Cody gives Xavier 31 stickers, Xavier will have 3 times as many stickers as him. Find
(a) Cody's stickers
(b) Xavier's stickers
|
Cody |
Xavier |
Total |
Before |
1 u + 31 |
3 u - 31 |
68 |
Change |
- 31 |
+ 31 |
|
After |
1 u |
3 u |
4 u |
(a)
Total number of stickers
= 1 u + 3 u
= 4 u
4 u = 68
1 u = 68 ÷ 4 = 17
Number of stickers that Cody has
= 1 u + 31
= 17 + 31
= 48
(b)
Number of stickers that Xavier has
= 68 - 48
= 20
Answer(s): (a) 48; (b) 20