Pierre and Daniel have a total of 70 pens. If Pierre gives Daniel 19 pens, Daniel will have 4 times as many pens as him. Find
(a) Pierre's pens
(b) Daniel's pens
|
Pierre |
Daniel |
Total |
Before |
1 u + 19 |
4 u - 19 |
70 |
Change |
- 19 |
+ 19 |
|
After |
1 u |
4 u |
5 u |
(a)
Total number of pens
= 1 u + 4 u
= 5 u
5 u = 70
1 u = 70 ÷ 5 = 14
Number of pens that Pierre has
= 1 u + 19
= 14 + 19
= 33
(b)
Number of pens that Daniel has
= 70 - 33
= 37
Answer(s): (a) 33; (b) 37