Lee and Brandon have a total of 66 buttons. If Lee gives Brandon 25 buttons, Brandon will have 5 times as many buttons as him. Find
(a) Lee's buttons
(b) Brandon's buttons
|
Lee |
Brandon |
Total |
Before |
1 u + 25 |
5 u - 25 |
66 |
Change |
- 25 |
+ 25 |
|
After |
1 u |
5 u |
6 u |
(a)
Total number of buttons
= 1 u + 5 u
= 6 u
6 u = 66
1 u = 66 ÷ 6 = 11
Number of buttons that Lee has
= 1 u + 25
= 11 + 25
= 36
(b)
Number of buttons that Brandon has
= 66 - 36
= 30
Answer(s): (a) 36; (b) 30