There were 58 more black buttons than gold buttons in a packet. Another 89 black buttons and 99 gold buttons were put into the packet. How many more black buttons than gold buttons were there in the end?
| |
Black |
Gold |
| Before |
1 u + 58 |
1 u |
| Change |
+ 89 |
+ 99 |
| After |
1 u + 147 |
1 u + 99 |
Number of black buttons in the end
= 1 u + 58 + 89
= 1 u + 147
Number of gold buttons = 1 u + 99
Number of black buttons more than gold buttons in the end
= 147 - 99
= 48
Answer(s): 48
