There were 49 more red buttons than green buttons in a packet. Another 66 red buttons and 54 green buttons were put into the packet. How many more red buttons than green buttons were there in the end?
|
Red |
Green |
Before |
1 u + 49 |
1 u |
Change |
+ 66 |
+ 54 |
After |
1 u + 115 |
1 u + 54 |
Number of red buttons in the end
= 1 u + 49 + 66
= 1 u + 115
Number of green buttons = 1 u + 54
Number of red buttons more than green buttons in the end
= 115 - 54
= 61
Answer(s): 61