There were 99 more black small pebbles than gold small pebbles in a packet. Another 99 black small pebbles and 63 gold small pebbles were put into the packet. How many more black small pebbles than gold small pebbles were there in the end?
|
Black |
Gold |
Before |
1 u + 99 |
1 u |
Change |
+ 99 |
+ 63 |
After |
1 u + 198 |
1 u + 63 |
Number of black small pebbles in the end
= 1 u + 99 + 99
= 1 u + 198
Number of gold small pebbles = 1 u + 63
Number of black small pebbles more than gold small pebbles in the end
= 198 - 63
= 135
Answer(s): 135