There were 21 more silver buttons than blue buttons in a packet. Another 53 silver buttons and 28 blue buttons were put into the packet. How many more silver buttons than blue buttons were there in the end?
| |
Silver |
Blue |
| Before |
1 u + 21 |
1 u |
| Change |
+ 53 |
+ 28 |
| After |
1 u + 74 |
1 u + 28 |
Number of silver buttons in the end
= 1 u + 21 + 53
= 1 u + 74
Number of blue buttons = 1 u + 28
Number of silver buttons more than blue buttons in the end
= 74 - 28
= 46
Answer(s): 46
